How was GATE 2021 AR? Short Polls:

Was GATE AR 2021 difficult than the GATE AR 2020?

  • Yes (69%, 318 Votes)
  • No (31%, 144 Votes)

Total Voters: 462

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What do you think the expected cut-off would be?

  • 33 to 35 (61%, 300 Votes)
  • 36 to 40 (22%, 109 Votes)
  • 41 to 45 (17%, 83 Votes)

Total Voters: 492

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The cut-off is surged to 40.9. What could be the reason?

  • 4 questions of total marks 6, are awarded to all candidates even if unattempted. (75%, 40 Votes)
  • The cut-off is not affected by 4 questions MTA (Marks To All) (25%, 13 Votes)

Total Voters: 53

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This page discuss about the Question & Answer of GATE 2021. The answer provided here comes with a few explanations. If you need better explanations/ Essential Notes for Q&A of GATE 2021, you are recommended to buy the following eBook from our Instamojo store:

 

Question & Answer GATE 2021

Aptitude Section

Q1.

Solution: Required probability = P(both are even) = P(first is even) * P(second is even) = (3/6)*(3/6) = (1/2)*(1/2)
= 1/4 Answer

Q2.

Solution:

The hatched region is called Secant of a circle. Area of secant = 1/4(Area of circle) – Area of triangle shown
= 1/4 (π r2) – 1/2 (base*height) = 1/4 (π r2) – 1/2 (r*r) = 1/4 (π r2) – 1/2 (r2) = 1/2(π/2 – 1)         [r = 1 given]There are two such Secants, So, area of dotted region surrounded by Secants shown in the question = 2*1/2(π/2 – 1)
= π/2 – 1
Area of square = r*r = 1*1 = 1

Therefore, Required probability = Area surrounded by Secants / Area of square = (π/2 – 1) / 1 = π/2 – 1 Answer

Q3.

Answer: (1)

Q4.

Q5.

Q6.

Answer: (3)

Q7.

Q8.

Q9.

Q10.

Answer: (4)

Architecture & Planning Section

Q11.

Answer: (1)

Q12.

Answer: (3)

Q13.

Answer: (3)

Q14.

Answer: (4)

Q15.

Answer: (1)

Q16.

Answer: (3) Invoke = Apply or implement, Revoke = cancel

Q17.

Q18.

Answer: (2)

Q19.

Answer: (4)

Q20.

Q21. (MSQ Type)

Q22.

Q23.

Q24.

Q25.

Q26.

Q27.

Q28.

Q29.

Answer: (2)

Q30. (MSQ Type)

Q31.

Q32.

Q33.

Q34.

Q35.

Q36.

Q37.

Q38.

Answer: (1)

Q39.

Answer: (4)

Q40.

Q41.

Q42.

Q43.

Q44.

Q45.

Q46.

Q47.

Q48.

Q49. (MSQ Type)

Q50.

Q51.

Q52.

Q53.

Q54.

Q55.

Q56.

Solution: Bending Stress = My/I
Where,
M = Bending Moment
I = Moment of Inertia (I = bd3/12 for a rectangular beam section of area bd)
y = Distance from neutral axis ( y = d/2 of depth d)

Q57. (MSQ Type)

Answer: (2) & (3)

Q58.

Answer: (4)

Q59.

Answer: (1)

Q60.

Q61.

Q62.

Answer: (4)

Q63.

Answer: (2)

Q64.

Answer: (2)

Q65. (MSQ Type)

This page is created on 6th February 2021.

11 replies
    • Jayati
      Jayati says:

      That ans will be 98.
      Total no of tiles coming as 104
      Flush door contain 6 tiles area.
      So (104-6) =98 is the ans

      Reply
  1. Prasenjit
    Prasenjit says:

    Mirror image,reverberation,tiles numerical, Jewish berlin museum, lumens numerical ( stadium light),temple architecture, max bending stress,thermal comfort index, Gordon Cullen ,bid rent theory,solar gain factor,landscape,

    Reply

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