How was GATE 2021 AR? Short Polls:

Was GATE AR 2021 difficult than the GATE AR 2020?

Total Voters: 462 Loading ...

What do you think the expected cut-off would be?

• 33 to 35 (61%, 300 Votes)
• 36 to 40 (22%, 109 Votes)
• 41 to 45 (17%, 83 Votes)

Total Voters: 492 Loading ...

The cut-off is surged to 40.9. What could be the reason?

• 4 questions of total marks 6, are awarded to all candidates even if unattempted. (75%, 40 Votes)
• The cut-off is not affected by 4 questions MTA (Marks To All) (25%, 13 Votes)

Total Voters: 53 Loading ...

#### This page discuss about the Question & Answer of GATE 2021. The answer provided here comes with a few explanations. If you need better explanations/ Essential Notes for Q&A of GATE 2021, you are recommended to buy the following eBook from our Instamojo store: #### Question & Answer GATE 2021

Aptitude Section

Q1.  Solution: Required probability = P(both are even) = P(first is even) * P(second is even) = (3/6)*(3/6) = (1/2)*(1/2) Q2. Solution: The hatched region is called Secant of a circle. Area of secant = 1/4(Area of circle) – Area of triangle shown
= 1/4 (π r2) – 1/2 (base*height) = 1/4 (π r2) – 1/2 (r*r) = 1/4 (π r2) – 1/2 (r2) = 1/2(π/2 – 1)         [r = 1 given]There are two such Secants, So, area of dotted region surrounded by Secants shown in the question = 2*1/2(π/2 – 1)
= π/2 – 1
Area of square = r*r = 1*1 = 1

Therefore, Required probability = Area surrounded by Secants / Area of square = (π/2 – 1) / 1 = π/2 – 1 Answer

Q3.  Answer: (1)

Q4.  Q5.  Q6.  Answer: (3)

Q7.  Q8. Q9. Q10. Answer: (4)

Architecture & Planning Section

Q11. Answer: (1)

Q12. Answer: (3)

Q13. Answer: (3)

Q14. Answer: (4)

Q15. Answer: (1)

Q16. Answer: (3) Invoke = Apply or implement, Revoke = cancel

Q17. Q18. Answer: (2)

Q19. Answer: (4)

Q20. Q21. (MSQ Type) Q22. Q23. Q24. Q25. Q26. Q27. Q28. Q29. Answer: (2)

Q30. (MSQ Type) Q31. Q32. Q33. Q34. Q35. Q36. Q37. Q38. Answer: (1)

Q39. Answer: (4)

Q40. Q41. Q42. Q43. Q44. Q45. Q46. Q47. Q48. Q49. (MSQ Type) Q50. Q51. Q52. Q53. Q54. Q55. Q56. Solution: Bending Stress = My/I
Where,
M = Bending Moment
I = Moment of Inertia (I = bd3/12 for a rectangular beam section of area bd)
y = Distance from neutral axis ( y = d/2 of depth d)

Q57. (MSQ Type) Answer: (2) & (3)

Q58. Answer: (4)

Q59. Answer: (1)

Q60. Q61. Q62. Answer: (4)

Q63. Answer: (2)

Q64. Answer: (2)

Q65. (MSQ Type) 11 replies
1. Lalit says:

I scored 64.33, what rank should i expect? any idea?

• Vinisha says:

Whats the score now

• Biswajeet says:

70.0

• Akhil says:

Hii

2. HIMANSHU SRIVASTAVA says:

NO. OF TILES USED?

• Jayati says:

That ans will be 98.
Total no of tiles coming as 104
Flush door contain 6 tiles area.
So (104-6) =98 is the ans

3. HariChaya says:

Is the answer key released all okay? Did anybody find any errors in the answers?

• Subba reddy says:

I think column slenderness ration is 20 not 40

• HariChaya says:

No that is right I think…radius of gyration is d/4….

• Subba reddy says:

Steel stress is 150 not 1.5

4. 